2x^2-16x+41=0

Solution for 2x^2-16x+41=0 equation:

Simplifying
2x2 + -16x + 41 = 0

Reorder the terms:
41 + -16x + 2x2 = 0

Solving
41 + -16x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
20.5 + -8x + x2 = 0

Move the constant term to the right:

Add '-20.5' to each side of the equation.
20.5 + -8x + -20.5 + x2 = 0 + -20.5

Reorder the terms:
20.5 + -20.5 + -8x + x2 = 0 + -20.5

Combine like terms: 20.5 + -20.5 = 0.0
0.0 + -8x + x2 = 0 + -20.5
-8x + x2 = 0 + -20.5

Combine like terms: 0 + -20.5 = -20.5
-8x + x2 = -20.5

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -20.5 + 16

Reorder the terms:
16 + -8x + x2 = -20.5 + 16

Combine like terms: -20.5 + 16 = -4.5
16 + -8x + x2 = -4.5

Factor a perfect square on the left side:
(x + -4)(x + -4) = -4.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.